InterviewSolution
Saved Bookmarks
| 1. |
The free energy of formation of NO is `78 kJ mol^(-1)` at the temperature of an authomobile engine `(1000 K)`. What is the equilibrium constant for this reaction at `1000 K`? `1/2 N_(2)(g)+1/2 O_(2)(g) hArr NO(g)`A. `8.4xx10^(-5)`B. `7.1xx10^(-9)`C. `4.2xx10^(-10)`D. `1.7xx10^(-19)` |
|
Answer» Correct Answer - A `K="antilog"[(-DeltaG^(@))/(2.303RT)]` `="antilog"[(-78xx1000)/(2.303xx8.314xx1000)]` `=8.4xx10^(-5)` |
|