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The frequency and intensity of a light source are both doubled. Consider the following statements A. The saturation photocurrent remains almost the same B. The maximum kinetic energy of the photoelectrons is doubleA. The saturation photocurrent gets doubleB. The saturation photocurrent remains almost the sameC. The maximum K.E. of the photoelectron is more than doubledD. The maximum K.E. of the photoelectrons gets double. |
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Answer» Correct Answer - a,c Saturation photoelectric current depends upon the intensity of the incident light. As `K_(max)=hv-phi_(0)`. If `v` becomes double, then `K_(max)` becomes more than double as `2hv-phi_(0)gt2(hv-phi_(0))` |
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