1.

The frequency (n)of vibration of a string is given as n=(1)/(2l)sqrt(T/(m)), where T is tension and l is the length of vibrating string, then the dimensional formula for m is :

Answer»

`[M^(0)L^(1)T^(1)]`
`[M^(0)L^(0)T^(0)]`
`[M^(1)L^(-1)T^(0)]`
`[ML^(0)T^(0)]`

Solution :`n=(1)/(2l)sqrt((T)/(m)):.n^(2)=(1)/(4l^(2))(T)/(m)`
`m=(T)/(4l^(2).n^(2))=(MLT^(-2))/(L^(2)xxT^(-2))=[ML^(-1)]`
Hence correct choice is `(C )`.


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