1.

The frequency of a light wave in a material is `2xx10^(14)Hz` and wavelength is `5000 Å`. The refractive index of material will beA. `1.40`B. `1.50`C. `3.00`D. `1.33S`

Answer» Correct Answer - C
Velocity of light waves in material is
`v=v lambda` ….`(i)`
Refractive index of material is
`mu=(c)/(v)` ....`(ii)`
where `c` is speed of light in vacuum or air.
or `mu=(c)/(vlambda)` ...`(iii)`
Given, `v=2xx10^(14)Hz,`
`lambda=5000 Å=5000 xx10^(-10)m,`
`c=3xx10^(8)m//s`
Hence, from Eq. `(iii)`, we get
`mu=(3xx10^(8))/(2xx10^(14)xx5000xx10^(-10))=3.00`


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