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The frequency of a light wave in a material is `2xx10^(14)Hz` and wavelength is `5000 Å`. The refractive index of material will beA. `1.40`B. `1.50`C. `3.00`D. `1.33S` |
Answer» Correct Answer - C Velocity of light waves in material is `v=v lambda` ….`(i)` Refractive index of material is `mu=(c)/(v)` ....`(ii)` where `c` is speed of light in vacuum or air. or `mu=(c)/(vlambda)` ...`(iii)` Given, `v=2xx10^(14)Hz,` `lambda=5000 Å=5000 xx10^(-10)m,` `c=3xx10^(8)m//s` Hence, from Eq. `(iii)`, we get `mu=(3xx10^(8))/(2xx10^(14)xx5000xx10^(-10))=3.00` |
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