The frequency of a simple pendulum is `n` oscillations per minute while that of another is `(n + 1)` oscillations per minute. The ratio of length of first second is-A. `(n)/(n+1)`B. `(n+(1)/(n))^(2)`C. `((n+1)/(n))^(2)`D. `((n)/(n+1))^(2)`

The frequency of a simple pendulum is `n` oscillations per minute whil

1.	The frequency of a simple pendulum is `n` oscillations per minute while that of another is `(n + 1)` oscillations per minute. The ratio of length of first second is-A. `(n)/(n+1)`B. `(n+(1)/(n))^(2)`C. `((n+1)/(n))^(2)`D. `((n)/(n+1))^(2)`
Answer» Correct Answer - C `T = 1/f = 2pisqrt((l)/(g)) rArr f = (1)/(2pi) sqrt((g)/(l))` `(f_(1))/(f_(2)) = sqrt((l_(2))/(l_(1))) rArr ((n)/(n+1))^(2) = (l_(2))/(l_(1)) rArr = (l_(1))/(l_(2)) = ((n+1)/(n))^(2)`

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The frequency of a simple pendulum is `n` oscillations per minute while that of another is `(n + 1)` oscillations per minute. The ratio of length of first second is-A. `(n)/(n+1)`B. `(n+(1)/(n))^(2)`C. `((n+1)/(n))^(2)`D. `((n)/(n+1))^(2)`

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