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The frequency of oscillations of a small magnet in a magnetic field of induction 2.4xx10^-4 Wb//m^2 is n. If the frequency of oscillations of same magnet becomesn/4. What is the value of new magnetic field ? |
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Answer» SOLUTION :`N=1/(2pi)sqrt((MB)/1)` `thereforen_1/n_2=sqrt(B_1/B_2)` `n/(n//4)=sqrt(B_1/B_2)` `THEREFORE 4^2=B_1/B_2.` |
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