1.

The frequency of radiation emitted when the electron falls from n = 4 to n = 1 in a hydrogen atom will be (given ionization energy of H=2.18xx10^(-18)J"atom"^(-1)andh=6.625xx10^(-34)Js

Answer»

`1.54xx10^(15)s^(-1)`
`1.03xx10^(15)s^(-1)`
`3.08xx10^(15)s^(-1)`
`2.00xx10^(15)s^(-1)`

SOLUTION :`DeltaE=hv=E_(1)(1/n_(1)^(2)-1/n_(2)^(2))`


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