InterviewSolution
Saved Bookmarks
| 1. |
The frequency of revolution of the electron in the second Bohr orbit in the hydrogen atom is 8.22 × 1014 Hz. What is the corresponding electric ’ current? [e = 1.6 × 10-19 C] |
|
Answer» I = \(\cfrac eT\) = ef = (1.6 × 10-19)(8.22 × 1014) = 1.315 × 10-4 A is the corresponding electric current. |
|