1.

The frequency of revolution of the electron in the second Bohr orbit in the hydrogen atom is 8.22 × 1014 Hz. What is the corresponding electric ’ current? [e = 1.6 × 10-19 C]

Answer»

I = \(\cfrac eT\) = ef

= (1.6 × 10-19)(8.22 × 1014)

= 1.315 × 10-4 A

is the corresponding electric current.



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