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The frequency of the first overtone of a closed pipe of length l_(1)is equal to that of the first overtone of an open pipe of length l_(1) . The ratio of their lengths (l_(1) : l_(2)) is |
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Answer» `2:3` `v_( c) =(3v)/(4l_(1))` Where v is the velocity of sound in air. The frequency of the first overtone of an open pipe of length `l_(2)` is `v_(O) =(2v)/(2l_(2)) =v/l_(2)` As per QUESTION, `v_( C) =v_(0)` `therefore 3/4 v/l_(1) = v/l_(2)` or `l_(1)/l_(2) = 3/4` |
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