1.

The frequency of the second overtone in a pipe open at both ends is n_(1). The frequency of the second overtone in a pipe of the same dimensions but closed at one end is n_(2). Then,

Answer»

`n_(1)=(6)/(5)n^(2)`
`n_(2)=(6)/(5)n_(1)`
`n_(1)=(4)/(5)n_(2)`
`n_(2)=(4)/(5)n_(1)`

Solution :`n_(1)=(3V)/(2L), n_(2)=(5V)/(4L)`


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