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The fuel in a rocket is burnt at the rate of 50 kg/s and the gases are ejected at the rate of 6 xx 10^4m/s with respect to the rocket, What is the thrust developed? |
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Answer» SOLUTION :Thrust = `V(dm)/dt`, V is the EXHAUST velocity of the EJECTED gases w.r.t the rocket = `6xx10^4xx50 = 3xx10^6N`. |
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