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The function f(x)=ex−1 is tto be solved using Newton-Raphson method. If the initial value of x0 is taken as 1.0, then the absolute error observed at 2nd iteration is0.06 |
Answer» The function f(x)=ex−1 is tto be solved using Newton-Raphson method. If the initial value of x0 is taken as 1.0, then the absolute error observed at 2nd iteration is
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