1.

The function sin^(2)(omega t) represents

Answer»

a PERIODIC, but not simple HARMONIC motion with period `2pi//omega`
a periodic, but not simple harmonic motion with period `pi//omega`
a simple harmonic motion with a period `2pi//omega `
a simple harmonic motion with a period `pi//omega`

Solution :Here, `y = sin^(2) omega t`

`(dy)/(dt) = 2omega sin omega t - omega sin 2omegat`
`(d^(2)y)/(dt^(2)) = 2omega^(2) cos2 omega t`
For SHM, `(d^(2)y)/(dt^(2))prop -y`
HENCE, function is not SHM, but periodic.
From the y-t graph, time period, `T = pi/omega`


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