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The function `t` which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by `t(C)=(9C)/5+32`.Find (i) `t (0)` (ii) `t(28)` (iii) `t(-10)` (iv) The value of C, when `t(C) = 212`.

Answer» `t(c) = (9C)/5 + 32`
(i) `t(0) = 9(0)/5 + 32= 32 F`
(ii) `t(28) = (9*98)/5 + 32 = 82.4F`
(iii) `t(-10) = (9*(-10))/5 + 32 = 14 F`
(iv) `C=? , t(C) = 212`
`(9C)/5 + 32 = 212`
`(9C)/5 = 180`
`C= 100^@`
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