The function y=f(x) is the solution of the differential equation dydx+ – InterviewSolution

InterviewSolution

1.	The function y=f(x) is the solution of the differential equation dydx+xyx2−1=x4+2x√1−x2 in (-1, 1) satisfying f(0) =0. Then ∫√32−√32f(x)d(x) is
Answer» The function $y = f (x)$ is the solution of the differential equation $\frac{d y}{d x} + \frac{x y}{x^{2} - 1} = \frac{x^{4} + 2 x}{\sqrt{1 - x^{2}}}$ in (-1, 1) satisfying f(0) =0. Then $\int_{\frac{- \sqrt{3}}{2}}^{\frac{\sqrt{3}}{2}} f (x) d (x)$ is

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