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The G.M. of two positive numbers is 6. Their arithmetic mean A and harmonic mean H satisfy the equation `90A+5H=918`, then A may be equal to (A) `5/2` (B) 10 (C) 5 (D) `1/5`A. `(1)/(5)`B. 5C. `(5)/(2)`D. 10 |
Answer» Correct Answer - A::D `:.G=6` and `G^(2)=AH` `implies H=(36)/(A)` Given, `90A+5H=918` `implies 90A+5xx(36)/(A)=918" " implies 5A+(10)/(A)=51` `implies 5A^(2)-51A+10=0" " implies (A-10)(5A-1)=0` `:.A=10,(1)/(5)` |
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