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    				| 1. | The gas having average speed four times as that of `SO_(2)` (molecular mass 64) isA. He (molecular mass 4)B. `O_(2)` (molecular mass 32)C. `H_(2)` (molecular mass 2)D. `CH_(4)` (molecular mass 16) | 
| Answer» Correct Answer - A Average speed `(v_("av"))` of gas molecules is inversely proportional to the square root of the absolute temperature (T) of the gas. `v_(av)=sqrt((8RT)/(piM))` When R is gas constant and M the molecular weight. Given, `v_(1)=v, M_(1)=64, v_(2)=4v` `(v)/(4v)=sqrt((M_(2))/(64))` `Rightarrow M_(2)=(64)/(16)=4` Hence, the gas is helium (molecular mass 4). | |