1.

The gas having average speed four times as that of `SO_(2)` (molecular mass 64) isA. He (molecular mass 4)B. `O_(2)` (molecular mass 32)C. `H_(2)` (molecular mass 2)D. `CH_(4)` (molecular mass 16)

Answer» Correct Answer - A
Average speed `(v_("av"))` of gas molecules is inversely proportional to the square root of the absolute temperature (T) of the gas. `v_(av)=sqrt((8RT)/(piM))`
When R is gas constant and M the molecular weight.
Given, `v_(1)=v, M_(1)=64, v_(2)=4v`
`(v)/(4v)=sqrt((M_(2))/(64))`
`Rightarrow M_(2)=(64)/(16)=4`
Hence, the gas is helium (molecular mass 4).


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