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    				| 1. | A parallel plate condenser with oil (dielectric constant 2) between the plates has capacitance C. If oil is removed, the capacitance of capacitor becomesA. `sqrt(2C)`B. 2CC. `(C)/(sqrt2)`D. `(C)/(2)` | 
| Answer» Correct Answer - D The capacitance of a parallel plate capacitor with dielectric (oil) between its plates is. `C=(Kepsi_(0)A)/(d).....(i)` where `epsi_(0)`,=electric permittivity of free space K=dielectric constant A=area of each plate of capacitor d=distance between two plates When dielectric (oil) is removed, so capacitance `c_(0)=(epsi_(0)A)/(d).....(ii)` Comparing Eqs. (i) and (iii), we get `C=KC_(0)` `Rightarrow C_(0)=(C)/(K)=(C)/(2) (therefore K=2)` | |