1.

the gas, the work dode by theg(a) 42.12 () 56.28 28571If2 moles of an ideal monoatomic gas at temperature T is mixed with 4 smoles of anothet idealgas at temperature 2T then the temperature of the miure is

Answer»

upon adding 2 mole of a gas with , 4 moles of another gas the total moles will be 6 moles

now for gas1, using gas equationPV = 2*R* T°

=> 2 = PV/RT°

for gas2 => PV = 4*R*(2T°)=> 4 = PV/2RT°

now adding both 2+4 = 6 => but on adding=> PV = 6*RT' => 6 = PV/RT'

and, PV/RT° + PV/R(2T°) = PV/RT' => 1/T° + 1/2T° = 1/T' => 1/T°(1+1/2) = 1/T'=> 3/2T° = 1/T'=> 2T°/3 = T'

so, the new temperature T' = 2T°/3.

but in book answer is 5/3T°

See this , if P and V are constant then,

n1T1 + n2T2 = ntotal*(T')

=> 2*T° + 4×(2T°) = (4+2)T' => 10T° = 6T'

=> T' = 10/6 = 5/3T°

but that approach should also be correct.. because here it is not mentioned that volume is constant or changing..

but use this as solution..


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