InterviewSolution
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InterviewSolution
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The general solution of the equation, `2cot.(theta)/(2)=(1+cot theta)^(2)` is `(n in Z)`A. `n pi+(-1)^(n)(pi)/(4)`B. `n pi+(-1)^(n)(pi)/(6)`C. `n pi+(-1)^(n)(pi)/(3)`D. none of these |
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Answer» Correct Answer - B `2cot.(theta)/(2)=(1+cot thetas)^(2)` `rArr (2.2 cos theta//2.cos theta//2)/(2 sin theta//2.cos theta//2)=(1+cos theta)^(2)` `rArr (2(1+cos theta))/(sin theta)=cosec^(2)theta + 2 cos theta` `rArr sin theta =1//2` `rArr theta = n pi +(-1)^(n)(pi)/(6), n in Z` |
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