InterviewSolution
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InterviewSolution
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The general solution of the equation `(dy)/(dx)=1+x y`is(a)`( b ) (c) y=c (d) e^( e ) (f)-( g )(( h ) (i) x^((( j )2( k ))( l ))/( m )2( n ) (o) (p))( q ) (r)`(s)(b) `( t ) (u) y=c (v) e^( w ) (x) (y)(( z ) (aa) x^((( b b )2( c c ))( d d ))/( e e )2( f f ) (gg) (hh))( i i ) (jj)`(kk)(c)`( d ) (e) y=(( f ) (g) x+c (h)),( i ) e^( j ) (k)-( l )(( m ) (n) x^((( o )2( p ))( q ))/( r )2( s ) (t) (u))( v ) (w)`(x) (d) None of theseA. `y=ce^(-x^(2)//2)`B. `y=ce^(x^(2)//2)`C. `y=(x+c),e^(-x^(2)//2)`D. None of these |
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Answer» Correct Answer - D `(dy)/(dx)=1+xy` or `(dy)/(dx)-xy=1` I.F. `=e^(int-xdx)=e^(-x^(2)//2)` Hence solution is `y.e^(-x^(2)//2) = inte^(-x^(2)+2)dx+c`. `inte^(-x^(2)//2)dx` is not further integrable. |
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