1.

The Gibbs energy for the decomposition of Al_(2)O_(3) at 500^(@)C is as follows: (2)/(3)Al_(2)O_(3)to(4)/(3)Al+O_(2),Delta_(r)G=+966 kJ mol^(-1) The potential difference needed for electrolytic reduction of Al_(2)O_(3) at 500^(@)C is at least.

Answer»

2.5 V
5.0 V
4.5V
3.0V

Solution :`(2)/(3)Al_(2)O_(3)to(4)/(3)Al+O_(2),Delta_(r)G=+966" kJ "MOL^(-1)`
Thus, `(2)/(3)XX(3O^(2-)), i.e., 2O^(2-)toO_(2),n=4`
`DeltaG=-nFE`
`therefore966xx10^(3)=-4xx96500xxE` or `E=-2.50V` ltBrgt Thus, minimum potential difference REQUIRED =2.50V.


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