1.

The given variable losses are 5kW fr a 500 KVA, 11 kV, 3-phase star connected alternator having armature resistance of 4 ohms. Calculate the current at which maximum efficiency occurs?(a) 20.4A(b) 10.2A(c) 40A(d) 26AThis question was posed to me in an interview for job.I would like to ask this question from Efficiency of Synchronous Machines topic in portion Efficiency and Regulation of Electrical Machines

Answer» RIGHT OPTION is (a) 20.4A

To EXPLAIN I would say: I^2=5000/3*4

I = 20.4 A.


Discussion

No Comment Found

Related InterviewSolutions