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The graph between log k and 1/T[K is rate constant (sec^(-1)) and T the temperature (K)] is a straight line with OX=5 and theta=tan^(-1)(-1/2.303).Calculate the value of E_a is cal. ? |
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Answer» THUS, `-E_a/(2.303R)=TAN theta=-1/2.303` `:. E_a=R=2` CAL.
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