

InterviewSolution
Saved Bookmarks
1. |
The graph between the stopping potential `V_(0)` and frequency `v` for two different metal plates `P` and `Q` are shown in the figure. Which of the metals has greater threshold wavelength and work function. |
Answer» `eV_(s)= hv-W` `W=(hc)/(lambda_(th))` From graph, `W_(Q) gt W_(p)` So work function of `Q` is greater than `P` `lambda_(th p) gt lambda_(th Q)` |
|