1.

The gravitational field due to a mass distribution is `E=(A)/(x^(2))` in x-direction. Here, A is a constant, Taking the gravitational potential to be zero at infinity, potential at x isA. `(2A)/(x)`B. `(2A)/(x^(3))`C. `(A)/(x)`D. `(A)/(2x^(2))`

Answer» Correct Answer - C


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