The gravitational field due to a mass distribution is given by `l=kx^(-3//2)` in x-direction, where k is a positive constant. Taking potential to be zero at infinity, find its value at a distance x.

The gravitational field due to a mass distribution is given by `l=kx^(

1.	The gravitational field due to a mass distribution is given by `l=kx^(-3//2)` in x-direction, where k is a positive constant. Taking potential to be zero at infinity, find its value at a distance x.
Answer» `V(x)=-int_(oo)^(x)ldx =-K int_(oo)^(x)x^(-3//2)dx= +2k [(1)/(sqrt(x))]_(oo)^(x)=(2k)/(sqrt(x))`

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The gravitational field due to a mass distribution is given by `l=kx^(-3//2)` in x-direction, where k is a positive constant. Taking potential to be zero at infinity, find its value at a distance x.

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