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The gravitational field due to mass distribution is E=K/x^2 in the X direction (K is stationary). Taking the gravitation potential be zero at infinity. Find the value of the gravitationl potential at a distance x. |
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Answer» Solution :`E=(-dv)/DX thereforedv=-dx` and `E=K/x^3 V=undersetxoversetoointK/x^3dx=K[x^(-3+1)/(-3+1)]_x^oo=-K/2[1/X^2]_x^ooV=-^K//_2[-1/x^2]=K/(2x^2)` |
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