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The gravitational field in a region due to a certain mass distribution is given by `vec(E)=(4hati-3hatj)N//kg`. The work done by the field in moving a particle of mass `2kg` from `(2m,1m)` to `(2/3m,2m)` along the line `3x+4y=10` isA. `-25/3 N`B. `-50/3 N`C. `25/3N`D. zero |
Answer» Correct Answer - B `W=m(vec(E).vec(dr))=m(vec(E).(vec(r)_(2)-vec(r)_(1)))` |
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