1.

The gravitational field in a region is given by `vecE = (3hati- 4hatj) N kg^(-1)`. Find out the work done (in joule) in displacing a particle by `1 m` along the line `4y = 3x + 9`.

Answer» For the line `4y=3x+9`
`4dy+3dx,4dy-3dx=0` ..(i)
For work in the region
`dW=vecE.(dxhati+dyhatj)=(3hati-4hatj).(dxhati+dyhatj)`
`=3dx-4dy` (from equation (i)) =0


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