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The gravitational field in a region is given by `vecE = (3hati- 4hatj) N kg^(-1)`. Find out the work done (in joule) in displacing a particle by `1 m` along the line `4y = 3x + 9`. |
Answer» For the line `4y=3x+9` `4dy+3dx,4dy-3dx=0` ..(i) For work in the region `dW=vecE.(dxhati+dyhatj)=(3hati-4hatj).(dxhati+dyhatj)` `=3dx-4dy` (from equation (i)) =0 |
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