InterviewSolution
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InterviewSolution
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The gravitational force between two objects is proportional to `1//R` (and not as `1//R^(2)`) where `R` is separation between them, then a particle in circular orbit under such a force would have its orbital speed `v` proportional toA. `1//R^(2)`B. `R^(0)`C. `R^(1)`D. `1//R` |
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Answer» Correct Answer - b `F=(K)/(R)=(Mv^(2))/(R)" hence "v prop R^(0)` |
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