1.

The greatest acceleration or deceleration that a train may have is a. The minimum time in which the train can get from one station to the next at a distance s is:

Answer»

`SQRT((s)/(a))`
`sqrt((2S)/(a))`
`2sqrt((s/a))`
`1/2 sqrt((s)/(a))`

SOLUTION :Here let the ACCELERATION and retardaion take placefor `t/2` sec each. Then
`S=(1)/(2)((at^(2))/(2))xxt` or `(at^(2))/(4)=S` or `t=2sqrt((S)/(a))`


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