1.

The greatest height to which a man can throw a ball is ‘A’, the greatest distance to which he can throw it will be :

Answer»

H
2h
3h
`h/2`

Solution :`H=(2u^(2)sin^(2)THETA)/G` when `theta=90^@`
Then `H_(max)=(u^(2))/g`
`R_(max)=u^(2)/g`
Clearly `R_(max)=2H_(max)=2h`


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