1.

The groud state energy of hydrogen atom is `-13.6 eV`. When its electron is in first excited state, its exciation energy isA. `3.4 eV`B. `6.8 eV`C. 10.2 eV`D. zero

Answer» Correct Answer - C
Excitation energy is defined as the energy required to take the electron from ground level orbit to any higher order orbit (i.e, `n = 2, 3, 4……)`.
Given, ground state energy of hydrogen atom
`E_(1)=- 13.6 eV`
Enegry of electron in first excited state (i.e., `n = 2)`
`E_(2) =- (13.6)/((2)^(2)) eV`
Therefore, exciation energy
`Delta E = E_(2) - E_(1)`
`=- (13.6)/(4) - (-13.6)`
`=- 3.4 + 13.6 = 10.2 eV`


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