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The groud state energy of hydrogen atom is `-13.6 eV`. When its electron is in first excited state, its exciation energy isA. `3.4 eV`B. `6.8 eV`C. 10.2 eV`D. zero |
Answer» Correct Answer - C Excitation energy is defined as the energy required to take the electron from ground level orbit to any higher order orbit (i.e, `n = 2, 3, 4……)`. Given, ground state energy of hydrogen atom `E_(1)=- 13.6 eV` Enegry of electron in first excited state (i.e., `n = 2)` `E_(2) =- (13.6)/((2)^(2)) eV` Therefore, exciation energy `Delta E = E_(2) - E_(1)` `=- (13.6)/(4) - (-13.6)` `=- 3.4 + 13.6 = 10.2 eV` |
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