1.

The ground (Fig.) shows the number of particles Nt emitted per second by a radioactive source as a function of time t The relationship between N_t and t is. .

Answer»

`N_t = 1000 e^-(20t//s)`
`N_t = 20 e^(-(20 t//s)`
`N_t = 3 e^(-(0.05 t//s)`
`N_t = 20 e^(-(0.05 t//s)`

Solution :(d) The graph can be REPRESENTED by the LINEAR equation as follows
`(1n N_t - 3)/(t - 0) = (0-3)/(60 -0)`
`rArr 1n N_t - 1n 20 = -(1)/(20) t [1n 20 = 3.00]`
`rArr 1n (N_t)/(20) = -0.05 t`
Hence, `N_t = 20 e^(-(0.05t//s))`.


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