1.

The ground state configuration of oxygen in OF_(2) is

Answer»

`1s^(2)2s^(2)2P^(4)`
`1s^(2)2s^(2)2p^(6)`
`1s^(2)2s^(2) 2p^(2)`
`1s^(2)2s^(2)2p^(3)`

Solution :In `OF_(2)`, OXYGEN exists as `O^(2+).(1s^(2) 2s^(2) 2p^(2))`


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