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The ground state energy of hydrogen atom is -13.6 eV. If an electron makes a transition from an energy level -0.85 eV to -1.51 eV, Calculate the wavelength of the spectral line emitted. To which series of hydrogen spectrum does this wavelength belong? |
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Answer» SOLUTION :Here `Delta E = E_(2) - E_(1) = -0.85 - (-1.51)` ` = 0.66 eV` `Delta E = 0.66 xx 1.6 xx 10^(-19)`J ` lambda = (he)/(Delta E) = (6.63 xx 10^(-34) xx 3 xx 10^(8))/(0.66 xx 1.6 xx 10^(-19))` ` = 18.84 xx 10^(-7)` `lambda = 18840 Å` This wavelength belongs to the Pachen series of the hydrogen spectrum. |
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