1.

The ground state energy of hydrogen atom is - 13.6 eV. When its electron is in the first excited state, its excitation energy is.

Answer»

6.8 EV
10.2eV
0
3.4 eV

Solution :`E_(1) = - 13.66 eV`
Infirstexcited state `E_(2) = (13.6)/((2)^(2)) = -3.4 eV`
`therefore ` Excitation energy ` = E_(2) = E_(1) =- 3.4 - (-13.6) eV = + 10.2 eV`


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