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The ground state energy of hydrogen atom is - 13.6 eV. When its electron is in the first excited state, its excitation energy is. |
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Answer» 6.8 EV Infirstexcited state `E_(2) = (13.6)/((2)^(2)) = -3.4 eV` `therefore ` Excitation energy ` = E_(2) = E_(1) =- 3.4 - (-13.6) eV = + 10.2 eV` |
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