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The ground state energy of hydrogen atom is - 13.6 eV. When electron is in excited state its excitation energy is ......

Answer»

`3.4eV`
`6.8eV`
`10.2eV`
0

Solution :When the electron is in the first excited state (N = 2) then its ENERGY,,

`DeltaE=E_(2)-E_(1) "also" E_(n)=-(13.6)/(n^(2))EV`
`:.DELTA=-(13.6)/(2^(2))-((13.6)/(1^(2)))`
`=-3.4+13.6`
`:.DeltaE=(-3.4)-(-13.6)=10.2eV`


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