1.

The ground state energy of hydrogen atom is -13.6 eV. Hence the energy of the electron of adoubly ionised lithium atom in its 1st orbit will be[2012(A)(i) -4.5 eV(iii) -40.8 eV(ii) -13.6 eV(iv)-122.4 ev

Answer»

E=-13.6Z^2/n^2eVn=1E=-13.6*3^2/1^2=-122.4eV



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