The H.C.F of 3(x2−9)(x+4) and 12(x−3)23(x2−9)(x+4) and 12(x−3)2 is

The H.C.F of 3(x2−9)(x+4) and 12(x−3)23(x2−9)(x+4) and

1.	The H.C.F of 3(x2−9)(x+4) and 12(x−3)23(x2−9)(x+4) and 12(x−3)2 is
Answer» <html><body><p>x2−3x+2=x2−2x−x+2x(x−2)−1(x−2)=(x−2)(x−1)Nowx2−4x+3=x2−3x−x+3x(x−3)−1(x−3)=(x−3)(x−1)<a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, the only <a href="https://interviewquestions.tuteehub.com/tag/common-923599" style="font-weight:bold;" target="_blank" title="Click to know more about COMMON">COMMON</a> <a href="https://interviewquestions.tuteehub.com/tag/factor-458892" style="font-weight:bold;" target="_blank" title="Click to know more about FACTOR">FACTOR</a> is (x-1</p></body></html>