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The `H-O-H` bond angle in water isA. `120^@`B. `109.5^@`C. `107^@`D. `104.5^@` |
Answer» Correct Answer - D `SN` of `O` in `H_2O` is `2+2=4`. Thus, `O` is `sp^3-`hybridized, has tetrahedral geometry, and angular shape. Due to lone pair-lone pair and lone pair-bond pair repulsion, the bond angle is reduced from `109.5^@` to `104.5^@`. |
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