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The half life for radioactive decay of ""^(14)C is 5730 years. An archaeological artifact containing wood hadonly 80% of the ""^(14)C found in living tree. Estimate the age of the sample. |
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Answer» SOLUTION :RADIOACTIVE decay follows FIRST order kinetics Decay constant (k) `=(0.693)/(t_(1//2))=(0.693)/(5730)"years"^(-1)` Using the equation for first order kinetics and substituting the VALUES, we get `t=(2.303)/(k)"log"([A]_(0))/([A])=(2.303)/((0.693//5730" years"^(-1)))"log"(100)/(80)` or `t=(2.303xx5730)/(0.693)xx0.0969"years"=1845` years Thus, age of the sample = 1845 years. |
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