1.

The half -life of (238)/(92) U undergoing a decay is 4.5 xx 10^(9) years. Calculate the activity of 10 g same of (238)/(92) U.

Answer»

SOLUTION :It is given that `T_(1//2) = 4.5 xx10^(9)y= 4.5 xx10^(9)xx3.154 xx10^(7)s = 1.42xx10^(17)s`
Number of atoms ( or NUCLIDES ) of `(238)/(92)U` present in 10 g sample
`N= (10)/(238)xxN_(A)= (10)/(238)xxN_(A)=(10)/(238)xx6.023xx10^(23) = 2.53xx10^(22)`
Activity of the sample R = `lambdaN = (0.693xx2.53xx10^(22))/(1.42xx10^(17))= 1.23xx10^(5)s^(-1)=1.23xx10^(5)` BQ


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