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The half life of a cobalt radio istope is 5.3 years. What strength will a milli curic source of isotope have after a period of one year? |
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Answer» 0.10 mci `N/N_(0) =R. =e^(-lambda//t) or log_(10)(N)/(N_(0)) =(lambda t)/(2.3026)` `or log_(10) (1/R.)=(0.693 xx t)/(2.3026 xx T)=(0.693 xx 1)/(203026 xx 5.3) [lambda=(0693)/(T)]` `or 1/(R.)=1.14 THEREFORE R.=(1)/(1.14) =0.87 m Ci` |
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