1.

The half-life of a radioactive isotope is 3 hours. Value of its disintegration constant is

Answer»

0.231 PER HR
2.31 per hr
0.2079 per hr
2.079 per hr

Solution :`K = (0.693)/(t_(1//2)) = (0693)/(3HR) = 0.231` per hr.


Discussion

No Comment Found

Related InterviewSolutions