1.

The half-life of a radioactive isotope is three hours. If the initial mass of the isotope were 256g, the mass of it remaining undecayed after 18 hours would be

Answer»

`4.0 G`
`8.0 g`
`12.0 g`
`16.0 g`

Solution :`N_(t) = N_(0) ((1)/(2))^(N) , N_(t) = 256 ((1)/(2))^(18//3) = 256 ((1)/(2))^(6) = 4`


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