1.

The half life of a radioactive substance is 20 minutes. The approximate time interval (t_2 - t_1) between the time t_(2)" when "2/3 of it has decayed and timet_(1)" when "1/3 of it had decayed is :

Answer»

14 min
20 min
28 min
7 min

Solution :`t_(1)=20 "MINUTES"`
`N=N_(0)e^(-lambdat_(2)) lambdat_(1)=ln 3`
`2/3 N_(0)=N_(0)e^(-lambdat_(2)) ""t_(1)=1/LAMBDA ln 3`
`2/3 N_(0)=N_(0)e^(-lambda t_(2))`
`t_(2)=1/lambda ln 3/2`
`t_(2)-t_(1)=1/lambda [ln 3/2-ln 3]`
`=1/lambda ln [1/2]=(0.693)/(lambda)`


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