1.

The half-life of a radioisotope is four hour. If the initial mass of the isotope was 200 g, the mass remaining after 24 hours undecayed is

Answer»

3.125 G
2.084 g
1.042 g
4.167 g

Solution :`(N)/(N_(0)) = ((1)/(2))^((T)/(t_(1//2))), (N)/(200)= ((1)/(2))^((24)/(4)), (N)/(200) = ((1)/(2))^(6)`
`N = (200)/(64) = 3.125 g`


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