1.

The half-life of Co^(60) is 7 years. If one g of it decays, the amount of the substance remaining after 28 years is

Answer»

0.25 G
0.125 g
0.0625 g
0.50 g

Solution :`n = (28)/(7) = 4, N = (N_(0))/(2^(n)), N = (1)/(2^(4)) = (1)/(16) = 0.0625 g`


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